Java security checking
I'm trying to make an application in Java to check my password security.
This is what I already did:
import java.util.Arrays;
public class BruteForce {
public static void main(String[] args) {
String password = "123123";
char[] charset = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ".toCharArray();
BruteForce bf = new BruteForce(charset, 1);
String attempt = bf.toString();
while (true) {
if (attempt.equals(password)) {
System.out.println("Password Found: " + attempt);
break;
}
attempt = bf.toString();
System.out.println("" + attempt);
bf.increment();
}
}
private char[] cs; // Character Set
private char[] cg; // Current Guess
public BruteForce(char[] characterSet, int guessLength) {
cs = characterSet;
cg = new char[guessLength];
Arrays.fill(cg, cs[0]);
}
public void increment() {
int index = cg.length - 1;
while(index >= 0) {
if (cg[index] == cs[cs.length-1]) {
if (index == 0) {
cg = new char[cg.length+1];
Arrays.fill(cg, cs[0]);
break;
}
else {
cg[index] = cs[0];
index--;
}
}
else {
cg[index] = cs[Arrays.binarySearch(cs, cg[index]) + 1];
break;
}
}
}
@Override
public String toString() {
return String.valueOf(cg);
}
}
But I take a long time to get the "123123" as password (Maybe I don't even get it, I'm not sure)...
Is there a better method to do this with upper/lower alphabetical letters and numbers? Thank you.
Copyright License: Author:「Qello Smithx」,Reproduced under the CC 4.0 BY-SA copyright license with link to original source & disclaimer. Link to:https://stackoverflow.com/questions/32975443/java-security-checking
About “Java security checking” questions
I am using JRE 1.7 with Unlimited java policy
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Provider[0]:: SUN 1.7
Provider[1]:: SunRsaSign 1.7
Provider[2]:: SunEC 1.7
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I'm trying to make an application in Java to check my password security.
This is what I already did:
import java.util.Arrays;
public class BruteForce {
public static void main(String[] args)...
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