Why am I not getting an error?

In the following program:

#include <iostream>
using namespace std;

int main(){

int i = 99;

for(int i = 1; i <= 10; i++)
{
    cout << i << endl;
}
cout << endl << endl;

cout << i << endl;

return 0;
}

I am not getting an error on compilation. My question is why this is happening. The int variable i was declared twice. The first time i was declared in the main() function and thus its scope will be this whole main() function including the for loop. The second time i was declared with the for loop and thus its scope will be only the for loop. So, now inside the scope of the for loop there exists two int variablesi. Shouldn't this be a cause of error? And if not why?

Second thing is the output I am getting:

1
2
3
4
5
6
7
8
9
10

99

I also don't understand the output. Why after the execution of the for loop, the value of i that is being printed is 99 and not 10.

Copyright License：
Author:「Natsu」,Reproduced under the CC 4.0 BY-SA copyright license with link to original source & disclaimer.
Link to：https://stackoverflow.com/questions/38930800/why-am-i-not-getting-an-error